document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949315>Question 949315</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a garden is 34 feet. I fthe lenght is 3 less than 3 times the width, what is the area in square feet of the garden </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579599 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579599\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a garden is 34 feet. If the length is 3 less than 3 times the width, what is the area in square feet of the garden<BR>\n" );
document.write( "Width=W: Length=L=3W-3; Perimeter=P=2(L+W)<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "34 ft=2(L+W) Divide each side by 2.<BR>\n" );
document.write( "17 ft=L+W Substitute for L.<BR>\n" );
document.write( "17 ft=(3W-3)+W Add 3 to each side.<BR>\n" );
document.write( "20 Ft=4W Divide each side by 4.<BR>\n" );
document.write( "5 ft=W  The width of the garden is 5 ft.<BR>\n" );
document.write( "L=3W-3=3(5 ft)-3=15 ft-3=12 ft The garden is 12 ft long.<BR>\n" );
document.write( "Area=L*W=12 ft*5 ft=60 sq ft ANSWER: The area of the garden is 60 sq ft.<BR>\n" );
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