document.write( "Question 949305: y=x-4000x^2/35739\r
\n" ); document.write( "\n" ); document.write( "Using this formula how far downrange does the cannonball travel?\r
\n" ); document.write( "\n" ); document.write( "What is the maximum height of the cannonball and how far downrange does that height occur?
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Algebra.Com's Answer #579597 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
Apparently \"y=x-4000x%5E2%2F35739\" is the height of a cannonball that has traveled a downrange distance of \"x\" , with \"x\" and \"y\" measured in some unit of length.
\n" ); document.write( "The cannonball will travel downrange until it its the ground when \"y=0\" .
\n" ); document.write( "That happens when
\n" ); document.write( "\"0=x-4000x%5E2%2F35739\"<-->\"0=x%281-4000x%2F35739%29\"<-->\"system%28x=0%2C%22or%22%2C1-4000x%2F35739=0%29\"<-->\"system%28x=0%2C%22or%22%2Cx=35739%2F4000%29\"<-->\"system%28x=0%2C%22or%22%2Cx=8.93475%29\" .
\n" ); document.write( "That means that the cannonball exits the cannon at ground level, and hits the ground at a distance of \"highlight%28x=8.93475%29\" downrange (in whatever units \"x\" is measured).
\n" ); document.write( "Halfway to that point (parabolas are symmetrical) the cannonball reaches its maximum height.
\n" ); document.write( "Naturally, that happens when
\n" ); document.write( "\"x=%281%2F2%29%2A%2835739%2F4000%29\"<--->\"1-4000x%2F35739=1-%284000%2F35739%29%281%2F2%29%2A%2835739%2F4000%29=1-1%2F2=1%2F2\" .
\n" ); document.write( "Then,
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\n" ); document.write( "Of course, those numbers are exact mathematical calculation results with way to many decimal places. Rounding would be a good idea.
\n" ); document.write( "I might say that the cannonball travels downrange a distance of \"8.9\" units,
\n" ); document.write( "and reaches a maximu height of \"2.2\" units.
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