document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949370>Question 949370</A>: <I><SPAN STYLE=\"word-break: break-all;\"> BILL CAN PAINT A HOUSE IN 2 DAYS, GEORGE CAN PAINT THE SAME HOUSE IN 3 DAYS, AND JEFF WILL TAKE 5 DAYS. HOW LONG WILL IT TAKE IF ALL 3 WORK TOGETHER? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579590 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579590\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x represent the time it takes together:<BR>\n" );
document.write( "1/2days + 1/3days + 1/5days = x \r<BR>\n" );
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document.write( "Let's multiply by a common denominator to get rid of the fractions:<BR>\n" );
document.write( "30(1/2days + 1/3days + 1/5days) = 30x <BR>\n" );
document.write( "= 15days + 10days + 6days = 30x Now add to simplify:<BR>\n" );
document.write( "31days = 30x Divide both sides by 30:<BR>\n" );
document.write( "31/30= x Now, 31 goes into 30 once and you have a remainder of 1, so<BR>\n" );
document.write( "we can re-write the answer as: x= 1 1/30 days. For your reference, 1/30 of a days equals 7 hours and 12 minutes, so we can write: x= 1day 7hours 12minutes.\r<BR>\n" );
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