document.write( "Question 949350: aolvw for x:(1/125)^(4-2x)=5*25^(3x-1) \n" ); document.write( "
Algebra.Com's Answer #579582 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! (1/125)^(4-2x)=5*25^(3x-1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1=(125)^(4-2x)*5*25^(3x-1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5*(5^3)^(4-2x)*(5^2)^(3x-1)=1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5*5^(3(4-2x))*5^(2(3x-1))=1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The base is 5, and the factors raised to different exponents, all from the same base of 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Addition of those exponents: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Revising the equation, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-- \n" ); document.write( "The initial steps, rendered,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |