document.write( "Question 949350: aolvw for x:(1/125)^(4-2x)=5*25^(3x-1) \n" ); document.write( "
Algebra.Com's Answer #579582 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
(1/125)^(4-2x)=5*25^(3x-1)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1=(125)^(4-2x)*5*25^(3x-1)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "5*(5^3)^(4-2x)*(5^2)^(3x-1)=1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "5*5^(3(4-2x))*5^(2(3x-1))=1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The base is 5, and the factors raised to different exponents, all from the same base of 5.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Addition of those exponents: \"1%2B3%284-2x%29%2B2%283x-1%29\"
\n" ); document.write( "\"1%2B12-6x%2B6x-2\"
\n" ); document.write( "\"13-2\"
\n" ); document.write( "\"11\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Revising the equation,
\n" ); document.write( "\"highlight_green%28cross%285%5E11=1%29%29\", which is false, so NO SOLUTION .\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "--
\n" ); document.write( "The initial steps, rendered,\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%281%2F125%29%5E%284-2x%29=5%2A25%5E%283x-1%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1=%28125%29%5E%284-2x%29%2A5%2A25%5E%283x-1%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5%2A%285%5E3%29%5E%284-2x%29%2A%285%5E2%29%5E%283x-1%29=1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5%2A5%5E%283%284-2x%29%29%2A5%5E%282%283x-1%29%29=1\"
\n" ); document.write( "
\n" ); document.write( "
\n" );