document.write( "Question 80787: A rectangular parking lot is 50 ft longer than it is wide. Determne the dimensions of the parking lot if it measures 250 ft. diagonally. \n" ); document.write( "
Algebra.Com's Answer #57958 by dolly(163)\"\" \"About 
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Let the width of the parking lot be 'x' ft
\n" ); document.write( "So length = (x+50) ft\r
\n" ); document.write( "\n" ); document.write( "Given the diagonal measures = 250 ft\r
\n" ); document.write( "\n" ); document.write( "The width, length and the diagonal together form a right triangle.
\n" ); document.write( "Applying Pythagorean theorem,
\n" ); document.write( "x^2 + (x+50)^2 = (250)^2
\n" ); document.write( "==> x^2 + x^2 + 100x + 2500 = 62500
\n" ); document.write( "==> 2x^2 + 100x + 2500 - 62500 = 0
\n" ); document.write( "==> 2x^2 + 100x - 60000 = 0
\n" ); document.write( "==> x^2 + 50x - 30000 = 0 [dividing by 2]
\n" ); document.write( "==> x^2 + 200x - 150x - 30000 = 0
\n" ); document.write( "==> x(x+200) - 150(x + 200) = 0
\n" ); document.write( "==> (x+200) (x-150) = 0
\n" ); document.write( "==> x+200 = 0 or x-150 = 0
\n" ); document.write( "As x denotes width, x cannot be negative.
\n" ); document.write( "Thus we take x = 150 only\r
\n" ); document.write( "\n" ); document.write( "So the length of the parking lot = x+50 = 200 ft
\n" ); document.write( "Width of the parking lot = x = 150 ft.\r
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