document.write( "Question 949323: The price of a screw is lowered by 1c.Before the reduction you could buy screws with 80c and get no change . Now you get one screw more and 3c change. Calculate the orignal price of one screw.\r
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document.write( "My solution:
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document.write( "Let x=price of each screw and Y= price of screws\r
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document.write( "Scenario 1. (X-1)
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document.write( "Scenario 2. ( Yx=80)
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document.write( "Scenario 3. (Y(x+1)=80-77) \n" );
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Algebra.Com's Answer #579578 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The price of a screw is lowered by 1c.Before the reduction you could buy screws with 80c and get no change . \n" ); document.write( " Now you get one screw more and 3c change. \n" ); document.write( " Calculate the original price of one screw. \n" ); document.write( ": \n" ); document.write( "I think we can do this with one variable \n" ); document.write( ": \n" ); document.write( "let x = the price of one screw originally \n" ); document.write( "then \n" ); document.write( "(x-1) = lowered price of a screw \n" ); document.write( "and \n" ); document.write( "( \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "multiply equation by x(x-1), resulting in \n" ); document.write( "77x = 80(x-1) + x(x-1) \n" ); document.write( "77x = 80x - 80 + x^2 - x \n" ); document.write( "0 = x^2 - x + 80x - 77x - 80 \n" ); document.write( "x^2 + 2x - 80 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(x+10)(x-8) = 0 \n" ); document.write( "the positive solution all we want here \n" ); document.write( "x = 8 cents for each screw originally \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See of that checks out \n" ); document.write( "Original number of screws: 80/8 = 10 each \n" ); document.write( "Lower price by one cent; number of screws: 77/7 = 11 each \n" ); document.write( " |