document.write( "Question 949323: The price of a screw is lowered by 1c.Before the reduction you could buy screws with 80c and get no change . Now you get one screw more and 3c change. Calculate the orignal price of one screw.\r
\n" ); document.write( "\n" ); document.write( "My solution:
\n" ); document.write( "Let x=price of each screw and Y= price of screws\r
\n" ); document.write( "\n" ); document.write( "Scenario 1. (X-1)
\n" ); document.write( "Scenario 2. ( Yx=80)
\n" ); document.write( "Scenario 3. (Y(x+1)=80-77)
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Algebra.Com's Answer #579578 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The price of a screw is lowered by 1c.Before the reduction you could buy screws with 80c and get no change .
\n" ); document.write( " Now you get one screw more and 3c change.
\n" ); document.write( " Calculate the original price of one screw.
\n" ); document.write( ":
\n" ); document.write( "I think we can do this with one variable
\n" ); document.write( ":
\n" ); document.write( "let x = the price of one screw originally
\n" ); document.write( "then
\n" ); document.write( "(x-1) = lowered price of a screw
\n" ); document.write( "and
\n" ); document.write( "(\"80%2Fx%29\" = original number of screws
\n" ); document.write( ":
\n" ); document.write( "\"77%2F%28%28x-1%29%29\" = \"80%2Fx\" + 1
\n" ); document.write( "multiply equation by x(x-1), resulting in
\n" ); document.write( "77x = 80(x-1) + x(x-1)
\n" ); document.write( "77x = 80x - 80 + x^2 - x
\n" ); document.write( "0 = x^2 - x + 80x - 77x - 80
\n" ); document.write( "x^2 + 2x - 80 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x+10)(x-8) = 0
\n" ); document.write( "the positive solution all we want here
\n" ); document.write( "x = 8 cents for each screw originally
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See of that checks out
\n" ); document.write( "Original number of screws: 80/8 = 10 each
\n" ); document.write( "Lower price by one cent; number of screws: 77/7 = 11 each
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