document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949343>Question 949343</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi!\r<BR>\n" );
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document.write( "I have been trying to solve this problem quite a while, and help for solving this would be great. \r<BR>\n" );
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document.write( "In a strict monarchy there are 100 monks, either senior or junior. If a senior monk is allowed to have 3 slices of break for each meal, and a junior monk is only allowed 1/3 of a slice, and altogether the consume 60 slices of break during lunch, how many senior monks are there?\r<BR>\n" );
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document.write( "I know that the answer is 10, but I was just wondering how it is possible to come to that answer.\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579575 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S=number of senior monks; J=number of junior monks<BR>\n" );
document.write( "S+J=100 Subtract S from each side<BR>\n" );
document.write( "J=100-S<BR>\n" );
document.write( "1/3J+3S=60 Substitute for J.<BR>\n" );
document.write( "1/3(100-S)+3S=60 <BR>\n" );
document.write( "33 1/3-1/3S+3S=60 Subtract 33 1/3 from each side.<BR>\n" );
document.write( "8/3 S=26 2/3 Multiply each side by 3/8.<BR>\n" );
document.write( "S=(80/3)*(3/8)=10 ANSWER: There are 10 senior monks.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "J=100-2=90 There are 90 junior monks,<BR>\n" );
document.write( "1/3J+3S=60<BR>\n" );
document.write( "1/3(90)+3(10)=60<BR>\n" );
document.write( "30+30=60 <BR>\n" );
document.write( "60=60\r<BR>\n" );
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document.write( " </SPAN>\n" );
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