document.write( "Question 949291: A satellite in geostationary orbit stays over the same spot on Earth. The satellite completes one orbit in the same time that Earth rotates once about its axis (23.93 hours) . If the satellite's orbit has radius 4.23 X 10 to the 7th power m, calculate the satellite's orbital speed (tangential velocity) in meters per second. \n" ); document.write( "
Algebra.Com's Answer #579543 by macston(5194)\"\" \"About 
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The circumference of the orbit is \"%28pi%29diameter\" so
\n" ); document.write( "\"Circumference=%28pi%29%288.46%2A10%5E7%29+m\"
\n" ); document.write( "This is the distance traveled in one period (23.93 hrs)
\n" ); document.write( "rate=distance/time=\"%28pi%29%288.46%2A10%5E7%29m%2F23.93hrs\"=\"%281.111%2A10%5E7%29+m%2Fhr\"
\n" ); document.write( "\"%281.111%2A10%5E7%29+m%2Fhr\"*\"%281+hr%2F3600+sec%29\"=3085.14 m/sec ANSWER The orbital speed of the satellite is 3085.14 m/sec.
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