document.write( "Question 949275: A yard has a perimeter of 184 feet. If six times the length of the yard equals seventeen times the width, what are the dimensions? \n" ); document.write( "
Algebra.Com's Answer #579527 by macston(5194)\"\" \"About 
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L=length=6/17W; W=width=17/6L; P=perimeter=2(L+W)
\n" ); document.write( "6L=17W Divide each side by 17
\n" ); document.write( "(6/17)L=W Multiply each side by 17/6
\n" ); document.write( "L=(17/6)W
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "184 ft=2(L+W) Divide each side by 2.
\n" ); document.write( "92 ft=L+W Substitute for L.
\n" ); document.write( "92 ft=(17/6)W+W Combine like terms.
\n" ); document.write( "92 ft=(17/6)W+(6/6)W
\n" ); document.write( "92 ft=(23/6)W Multiply each side by (6/23)
\n" ); document.write( "(6/23)(92 ft)=W
\n" ); document.write( "6*4 ft=W
\n" ); document.write( "24 ft=W ANSWER 1: The width is 24 ft.
\n" ); document.write( "L=(17/6)W
\n" ); document.write( "L=(17/6)(24 ft)
\n" ); document.write( "L=17*4 ft=68 ft ANSWER 2: Length is 68 ft.
\n" ); document.write( "The yard is 68 feet by 24 feet.
\n" ); document.write( "CHECK:
\n" ); document.write( "Perimeter=2(L+W)
\n" ); document.write( "184 ft=2(68 ft + 24 ft)
\n" ); document.write( "184 ft=2(92 ft)
\n" ); document.write( "184 ft=184 ft
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