document.write( "Question 949270: Given the functions \"+f%28x%29+=+3x+%2B+2+-+4%2Fx+\" and \"+g%28x%29+=+2+-+3x+\" , find the indicated values.\r
\n" ); document.write( "\n" ); document.write( " a) \"+f%28a%2Bb%29+\"
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\n" ); document.write( " b) \"+g%28a%29+-+g%28a-b%29+%2B+f%28a%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Please explain how you figured out the answer, I appreciate any help you can provide. Thank you!
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Algebra.Com's Answer #579512 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Given the functions f(x) = 3x + 2 - 4/x and g(x) = 2 - 3x , find the indicated values.\r
\n" ); document.write( "\n" ); document.write( " a) f(a+b)= 3(a+b) + 2 - 4/(a+b) = [3(a+b)^2 + 2(a+b) - 4]/(a+b)
\n" ); document.write( "= [3a^2 + 6ab + 3b^2 + 2a + 2b]/(a+b)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "b) g(a) - g(a-b) + f(a)
\n" ); document.write( "[2-3a - [2-3(a-b)] + [3a+2]
\n" ); document.write( "=====
\n" ); document.write( "= 2-3a-[2-3a+3b] + 3a+2
\n" ); document.write( "------
\n" ); document.write( "= 2-3a-2+3a-3b+3a+2
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\n" ); document.write( "= 3a -3b +2
\n" ); document.write( "--------------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "------------ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Please explain how you figured out the answer, I appreciate any help you can provide. Thank you!
\n" ); document.write( "
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