document.write( "Question 949258: Two cards are drawn without replacement from a ordinary deck, find the probability that the second is a face card, given that the first is not a face card. \n" ); document.write( "

Algebra.Com's Answer #579509 by Fombitz(32388) $\"\"$ $\"About$

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A-first card is not a face card
\n" ); document.write( "B-second card is a face card
\n" ); document.write( "P(A_and_B)=P(A)*P(B|A)
\n" ); document.write( "P(B|A)=P(A_and_B)/P(A)
\n" ); document.write( "There are 12 face cards in a standard deck.
\n" ); document.write( " $\"P%28A%29=%2852-12%29%2F52=10%2F13\"$
\n" ); document.write( " $\"P%28B%29=12%2F51\"$
\n" ); document.write( " $\"P%28A_and_B%29=P%28A%29%2AP%28B%29=%2810%2F13%29%2812%2F51%29=40%2F221\"$
\n" ); document.write( "So then,
\n" ); document.write( "P(B|A)= $\"%2840%2F221%29%2F%2810%2F13%29\"$
\n" ); document.write( "P(B|A)= $\"highlight%2812%2F51%29\"$ \r
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