document.write( "Question 949225: A lorry and a car both travel a 240 mile journey at constant speeds. \r
\n" ); document.write( "\n" ); document.write( "The car is travelling at 12mph faster than the lorry. \r
\n" ); document.write( "\n" ); document.write( "The lorry takes one hour longer to complete the journey.\r
\n" ); document.write( "\n" ); document.write( "If 'x' is the speed of the car, show an algebraic equation to show 'x'.\r
\n" ); document.write( "\n" ); document.write( "I have worked out (in my head) that the car is travelling at 60mph and takes 4 hours, the lorry at 48mph for 5 hours. I am struggling to show this as an equation, please help!!!
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Algebra.Com's Answer #579476 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
A lorry and a car both travel a 240 mile journey at constant speeds. \r
\n" ); document.write( "\n" ); document.write( "The car is travelling at 12mph faster than the lorry. \r
\n" ); document.write( "\n" ); document.write( "The lorry takes one hour longer to complete the journey.\r
\n" ); document.write( "\n" ); document.write( "If 'x' is the speed of the car, show an algebraic equation to show 'x'.
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\n" ); document.write( "t = d/r
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\n" ); document.write( "Time for the car = 240/x hours
\n" ); document.write( "Time for the lorry = 240/(x-12)
\n" ); document.write( "(240/x) + 1 = 240/(x-12)
\n" ); document.write( "(240 + x)/x = 240/(x-12)
\n" ); document.write( "(x+240)*(x-12) = 240x
\n" ); document.write( "\"x%5E2+%2B+228x+-+2880+=+240x\"
\n" ); document.write( "\"x%5E2+-+12x+-+2880+=+0\"
\n" ); document.write( "(x - 60)*(x + 48) = 0
\n" ); document.write( "x = 60
\n" ); document.write( "Ignore the x = -48\r
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