document.write( "Question 949225: A lorry and a car both travel a 240 mile journey at constant speeds. \r
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document.write( "The car is travelling at 12mph faster than the lorry. \r
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document.write( "The lorry takes one hour longer to complete the journey.\r
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document.write( "If 'x' is the speed of the car, show an algebraic equation to show 'x'.\r
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document.write( "I have worked out (in my head) that the car is travelling at 60mph and takes 4 hours, the lorry at 48mph for 5 hours. I am struggling to show this as an equation, please help!!! \n" );
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Algebra.Com's Answer #579476 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A lorry and a car both travel a 240 mile journey at constant speeds. \r \n" ); document.write( "\n" ); document.write( "The car is travelling at 12mph faster than the lorry. \r \n" ); document.write( "\n" ); document.write( "The lorry takes one hour longer to complete the journey.\r \n" ); document.write( "\n" ); document.write( "If 'x' is the speed of the car, show an algebraic equation to show 'x'. \n" ); document.write( "================= \n" ); document.write( "t = d/r \n" ); document.write( "------ \n" ); document.write( "Time for the car = 240/x hours \n" ); document.write( "Time for the lorry = 240/(x-12) \n" ); document.write( "(240/x) + 1 = 240/(x-12) \n" ); document.write( "(240 + x)/x = 240/(x-12) \n" ); document.write( "(x+240)*(x-12) = 240x \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(x - 60)*(x + 48) = 0 \n" ); document.write( "x = 60 \n" ); document.write( "Ignore the x = -48\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |