document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949267>Question 949267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Is it possible for x=-2 to be in the Domains of the functions:\r<BR>\n" );
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document.write( "a.)             R(x)= 3x^3 - 5x + 6 (all over) x + 2  \r<BR>\n" );
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document.write( "b.) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+H%28x%29=+sqrt%28+x%2B1+%29+ ALIGN=MIDDLE  ALT=\"+H%28x%29=+sqrt%28+x%2B1+%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Explain why or why not for each function. What are the Domains of the functions R(x) and H(x)? If required, use inf for the infinity sign.\r<BR>\n" );
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document.write( " Thank You for any help you can provide, I cannot find how to figure out these questions in my notes anywhere so if you can explain how you received each answer that would be great. Thank you again!\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579474 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579474\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> divided by x+2 means that it is equal to 0 if x = -2 which means it can't be in the domain because then the value of R(x) is undefined because of a division by 0.\r<BR>\n" );
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document.write( "when x = -2, sqrt(x+1) is equal to -1 so x = -2 can't be in the domain because the answer would not be real.  You would get sqrt(-1) which is imaginary.<BR>\n" );
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