document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949259>Question 949259</A>: <I><SPAN STYLE=\"word-break: break-all;\"> eight times a number plus five time another number is -13. The sum of the two numbers is 1. What are the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579464 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579464\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F=first number; S=second number<BR>\n" );
document.write( "F+S=1 Subtract S from each side.<BR>\n" );
document.write( "F=1-S<BR>\n" );
document.write( "8F+5S=-13 Substitute for F.<BR>\n" );
document.write( "8(1-S)+5S=-13<BR>\n" );
document.write( "8-8S+5S=-13 Subtract 8 from each side<BR>\n" );
document.write( "-3S=-21 Divide each side by -3<BR>\n" );
document.write( "S=7 ANSWER 1: The second number is 7<BR>\n" );
document.write( "F=1-S=1-7=-6 ANSWER 2: The first number is -6.<BR>\n" );
document.write( "CHECK<BR>\n" );
document.write( "8F+5S=-13 <BR>\n" );
document.write( "8(-6)+5(7)=-13<BR>\n" );
document.write( "-48+35=-13<BR>\n" );
document.write( "-13=-13 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );