document.write( "Question 949243: The formula for calculating simple interest is I=prt, where I is the amount of interest, p is the amount invested, r is the annual rate of interest, and t is the time in years. Suppose that you invested $1200 for a period of six years and earned $396 simple interest. What was the annual rate of interest?\r
\n" ); document.write( "\n" ); document.write( "a. 0.055%
\n" ); document.write( "b. 18%
\n" ); document.write( "c. 0.55%
\n" ); document.write( "d. 5.5%
\n" ); document.write( "

Algebra.Com's Answer #579445 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "The formula for calculating simple interest is
\n" ); document.write( "\"I=prt\", where \"I+\"is the amount of interest, \"p\" is the amount invested, \"r+\"is the annual rate of interest, and \"t\" is the time in years. \r
\n" ); document.write( "\n" ); document.write( "Suppose that you invested $\"1200\" for a period of six years and earned $\"396\" simple interest. What was the annual rate of interest? \r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "$\"I=396\"
\n" ); document.write( "$\"p=1200\"
\n" ); document.write( "\"t=6\"\r
\n" ); document.write( "\n" ); document.write( "find \"r+\"\r
\n" ); document.write( "\n" ); document.write( "\"I=prt\" .......plug in given values\r
\n" ); document.write( "\n" ); document.write( "\"396=1200%2Ar%2A6\".....solve for \"r\"\r
\n" ); document.write( "\n" ); document.write( "\"396=7200%2Ar\"\r
\n" ); document.write( "\n" ); document.write( "\"396%2F7200=r\"\r
\n" ); document.write( "\n" ); document.write( "\"r=0.055\" or \"r=5.5\"%\r
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\n" ); document.write( "\n" ); document.write( "so, your answer is option d. \"5.5\"%\r
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