document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949211>Question 949211</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Which point satisfies both equations?<BR>\n" );
document.write( "3x + 4y = 14<BR>\n" );
document.write( "x = 2y - 12<BR>\n" );
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document.write( "A)<BR>\n" );
document.write( "(-2,-2)	<BR>\n" );
document.write( "B)<BR>\n" );
document.write( "(-2,5)	<BR>\n" );
document.write( "C)<BR>\n" );
document.write( "(-4,4)	<BR>\n" );
document.write( "D)<BR>\n" );
document.write( "(2,2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579432 by </B><A HREF=/tutors/aboutme.mpl?userid=Zucchini><B>Zucchini(70)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Zucchini><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579432\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Plug in for x and solve: \r<BR>\n" );
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document.write( "3(2y - 12) + 4y = 14<BR>\n" );
document.write( "6y - 36 + 4y = 14<BR>\n" );
document.write( "10y = 50<BR>\n" );
document.write( "Y = 5\r<BR>\n" );
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document.write( "B is the only one with \"5\" in the y spot, so it's b, you will also get that if you plug y in for the other equation </SPAN>\n" );
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