document.write( "Question 949211: Which point satisfies both equations?
\n" ); document.write( "3x + 4y = 14
\n" ); document.write( "x = 2y - 12
\n" ); document.write( "
\n" ); document.write( "A)
\n" ); document.write( "(-2,-2)
\n" ); document.write( "B)
\n" ); document.write( "(-2,5)
\n" ); document.write( "C)
\n" ); document.write( "(-4,4)
\n" ); document.write( "D)
\n" ); document.write( "(2,2)
\n" ); document.write( "

Algebra.Com's Answer #579431 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
We are given
\n" ); document.write( "3x + 4y = 14
\n" ); document.write( "x = 2y - 12
\n" ); document.write( "******
\n" ); document.write( "from the second equation we know x = 2y - 12, therefore
\n" ); document.write( "substitute for x in the first equation
\n" ); document.write( "3(2y - 12) +4y = 14
\n" ); document.write( "6y - 36 + 4y = 14
\n" ); document.write( "combine like terms
\n" ); document.write( "10y = 50
\n" ); document.write( "y = 5
\n" ); document.write( "x = 2*5 - 12
\n" ); document.write( "x = -2
\n" ); document.write( "our answer is (-2, 5)
\n" ); document.write( "which is answer B
\n" ); document.write( "******
\n" ); document.write( "check our answer by substituting for x and y in the first equation
\n" ); document.write( "(3*-2) + (4*5) = 14
\n" ); document.write( "-6 + 20 = 14
\n" ); document.write( "14 = 14
\n" ); document.write( "our answer checks\r
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