document.write( "Question 949211: Which point satisfies both equations?
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document.write( "3x + 4y = 14
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document.write( "x = 2y - 12
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document.write( "A)
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document.write( "(-2,-2)
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document.write( "B)
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document.write( "(-2,5)
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document.write( "C)
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document.write( "(-4,4)
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document.write( "D)
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document.write( "(2,2) \n" );
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Algebra.Com's Answer #579431 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! We are given \n" ); document.write( "3x + 4y = 14 \n" ); document.write( "x = 2y - 12 \n" ); document.write( "****** \n" ); document.write( "from the second equation we know x = 2y - 12, therefore \n" ); document.write( "substitute for x in the first equation \n" ); document.write( "3(2y - 12) +4y = 14 \n" ); document.write( "6y - 36 + 4y = 14 \n" ); document.write( "combine like terms \n" ); document.write( "10y = 50 \n" ); document.write( "y = 5 \n" ); document.write( "x = 2*5 - 12 \n" ); document.write( "x = -2 \n" ); document.write( "our answer is (-2, 5) \n" ); document.write( "which is answer B \n" ); document.write( "****** \n" ); document.write( "check our answer by substituting for x and y in the first equation \n" ); document.write( "(3*-2) + (4*5) = 14 \n" ); document.write( "-6 + 20 = 14 \n" ); document.write( "14 = 14 \n" ); document.write( "our answer checks\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |