document.write( "Question 949113: the length of a rectangle is 13 centimeters less than six times its width. it's area is 15 square centimeters. find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #579404 by macston(5194)\"\" \"About 
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W=width; L=length=6W-13 cm;A=L*W=15 sq cm
\n" ); document.write( "A=L*W
\n" ); document.write( "15 sq cm=L*W Substitute for L.
\n" ); document.write( "15 sq cm=(6W-13)(W)
\n" ); document.write( "\"15+sq+cm=6W%5E2-13W\" Subtract 15 sq cm from each side.
\n" ); document.write( "\"0=6W%5E2-13W-15+sq+cm\"
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aW%5E2%2BbW%2Bc=0\" (in our case \"6W%5E2%2B-13W%2B-15+=+0\") has the following solutons:
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\n" ); document.write( " \"W%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-13%29%5E2-4%2A6%2A-15=529\".
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\n" ); document.write( " Discriminant d=529 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--13%2B-sqrt%28+529+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"W%5B1%5D+=+%28-%28-13%29%2Bsqrt%28+529+%29%29%2F2%5C6+=+3\"
\n" ); document.write( " \"W%5B2%5D+=+%28-%28-13%29-sqrt%28+529+%29%29%2F2%5C6+=+-0.833333333333333\"
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\n" ); document.write( " Quadratic expression \"6W%5E2%2B-13W%2B-15\" can be factored:
\n" ); document.write( " \"6W%5E2%2B-13W%2B-15+=+6%28W-3%29%2A%28W--0.833333333333333%29\"
\n" ); document.write( " Again, the answer is: 3, -0.833333333333333.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+6%2Ax%5E2%2B-13%2Ax%2B-15+%29\"

\n" ); document.write( "\n" ); document.write( "The answer we want is 3 ANSWER: Width is 3 cm.
\n" ); document.write( "L=6W-13=6(3)-13=18-13=5 cm ANSWER: Length is 5 cm.
\n" ); document.write( "CHECk:
\n" ); document.write( "A=L*W
\n" ); document.write( "15 sq cm=5 cm*3 cm
\n" ); document.write( "15 sq cm=15 sq cm
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