document.write( "Question 949097: (t/t+1)^2-(t/t+1)-12=0 \n" ); document.write( "
Algebra.Com's Answer #579389 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "(t/t+1)^2-(t/t+1)-12=0
\n" ); document.write( "
\"%28t%2F%28t+%2B+1%29%29%5E2+-+%28t%2F%28t+%2B+1%29%29+-+12+=+0\"
\n" ); document.write( "Let a = \"%28t%2F%28t+%2B+1%29%29\"
\n" ); document.write( "Then \"%28t%2F%28t+%2B+1%29%29%5E2+-+%28t%2F%28t+%2B+1%29%29+-+12+=+0\" becomes: \"a%5E2+-+a+-+12+=+0\"
\n" ); document.write( "(a - 4)(a + 3) = 0
\n" ); document.write( "a - 4 = 0 OR a + 3 = 0
\n" ); document.write( "a = 4 OR a = - 3\r
\n" ); document.write( "\n" ); document.write( "\"4+=+%28t%2F%28t+%2B+1%29%29\" ------- Substituting 4 for a
\n" ); document.write( "4(t + 1) = t ------ Cross-multiplying
\n" ); document.write( "4t + 4 = t
\n" ); document.write( "4t - t = - 4
\n" ); document.write( "3t = - 4
\n" ); document.write( "\"highlight_green%28t+=+-+4%2F3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"-+3+=+%28t%2F%28t+%2B+1%29%29\" ------- Substituting - 3 for a
\n" ); document.write( "- 3(t + 1) = t ----- Cross-multiplying
\n" ); document.write( "- 3t - 3 = t
\n" ); document.write( "- 3t - t = 3
\n" ); document.write( "- 4t = 3
\n" ); document.write( "\"highlight_green%28t+=+-+3%2F4%29\" \n" ); document.write( "
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