document.write( "Question 949111: an object is dropped from 38 feet below the tip of the pinnacle atop a 1482-ft tall building. the height h of the object after t seconds is given by the equation h=-16t^2+1444. find how many seconds pass before the object reaches the ground. \n" ); document.write( "
Algebra.Com's Answer #579381 by macston(5194)\"\" \"About 
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The point when it will hit the ground is when h=0
\n" ); document.write( "-16t^2+1444=0
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"at%5E2%2Bbt%2Bc=0\" (in our case \"-16t%5E2%2B0t%2B1444+=+0\") has the following solutons:
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\n" ); document.write( " \"t%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%280%29%5E2-4%2A-16%2A1444=92416\".
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\n" ); document.write( " Discriminant d=92416 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-0%2B-sqrt%28+92416+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"t%5B1%5D+=+%28-%280%29%2Bsqrt%28+92416+%29%29%2F2%5C-16+=+-9.5\"
\n" ); document.write( " \"t%5B2%5D+=+%28-%280%29-sqrt%28+92416+%29%29%2F2%5C-16+=+9.5\"
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\n" ); document.write( " Quadratic expression \"-16t%5E2%2B0t%2B1444\" can be factored:
\n" ); document.write( " \"-16t%5E2%2B0t%2B1444+=+-16%28t--9.5%29%2A%28t-9.5%29\"
\n" ); document.write( " Again, the answer is: -9.5, 9.5.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+-16%2Ax%5E2%2B0%2Ax%2B1444+%29\"
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\n" ); document.write( "The answer is 9.5 seconds
\n" ); document.write( "CHECK
\n" ); document.write( "0=-16t^2+1444
\n" ); document.write( "0=-16(9.5)^2 + 1444
\n" ); document.write( "0=-16(90.25)+1444
\n" ); document.write( "0==1444+1444
\n" ); document.write( "0=0
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