document.write( "Question 949086: 2508 is the area of a rectangle and 202 is the
\n" ); document.write( "perimeter what is the length; width?
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Algebra.Com's Answer #579379 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "2508 is the area of a rectangle and 202 is the
\n" ); document.write( "perimeter what is the length; width?
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\n" ); document.write( "Let length and width be L and W, respectively
\n" ); document.write( "Then: LW = 2,508 ------- eq (i)
\n" ); document.write( "Also, 2(L + W) = 202______2(L + W) = 2(101)______L + W = 101______W = 101 - L ------ eq (ii)
\n" ); document.write( "L(101 - L) = 2,508 ------- Substituting 101 - L for W in eq (i)
\n" ); document.write( "\"101L+-+L%5E2+=+2508\"
\n" ); document.write( "\"L%5E2+-+101L+%2B+2508+=+0\"
\n" ); document.write( "\"L%5E2+-+57L+-+44L+%2B+2508+=+0\"
\n" ); document.write( "\"L%28L+-+57%29+-+44%28L+-+57%29+=+0\"
\n" ); document.write( "(L - 44)(L - 57) = 0
\n" ); document.write( "L - 44 = 0 OR L - 57 = 0
\n" ); document.write( "L = 44 OR L = 57\r
\n" ); document.write( "\n" ); document.write( "This means that if length = 44, then width = 57
\n" ); document.write( "However, if length = 57, then width = 44
\n" ); document.write( "Thus, dimensions are: \"highlight_green%2844_units_by_57_units%29\" \n" ); document.write( "
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