document.write( "Question 949086: 2508 is the area of a rectangle and 202 is the
\n" ); document.write( "perimeter what is the length; width?
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Algebra.Com's Answer #579354 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
w, width
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\n" ); document.write( "p, perimeter
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\n" ); document.write( "\n" ); document.write( "FORMULAS
\n" ); document.write( "2w+2L=p;
\n" ); document.write( "wL=A.\r
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\n" ); document.write( "\n" ); document.write( "KNOWN VARIABLES:
\n" ); document.write( "p=202
\n" ); document.write( "A=2508
\n" ); document.write( "UNKNOWN VARIABLES:
\n" ); document.write( "w, L.\r
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\n" ); document.write( "\n" ); document.write( "SOLVE FOR UNKNOWN VARIABLES\r
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\n" ); document.write( "\n" ); document.write( "\"2L=p-2w\"
\n" ); document.write( "\"L=%28p-2w%29%2F2\"
\n" ); document.write( "-
\n" ); document.write( "\"wL=A\"
\n" ); document.write( "\"w%28p-2w%29%2F2=A\"
\n" ); document.write( "\"w%28p-2w%29=2A\"
\n" ); document.write( "\"pw-2w%5E2=2A\"
\n" ); document.write( "\"-2w%5E2%2Bpw-2A=0\"
\n" ); document.write( "\"2w%5E2-pw%2B2A=0\"
\n" ); document.write( "Just know that sometimes, the actual values can make the equation here easier to work with.
\n" ); document.write( "You may want to choose the substitute the given values NOW into this quadratic equation before
\n" ); document.write( "continuing. That is what will do here:
\n" ); document.write( "\"2w%5E2-202w%2B2%2A2508=0\"
\n" ); document.write( "\"w%5E2-101w%2B2508=0\"
\n" ); document.write( "-
\n" ); document.write( "\"w=%28101%2B-+sqrt%28101%5E2-4%2A2508%29%29%2F2\"
\n" ); document.write( "\"w=%28101%2B-+13%29%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"highlight%28w=44%29\" OR \"highlight%28w=57%29\"\r
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\n" ); document.write( "\n" ); document.write( "Finding corresponding L values from earlier found formula \"L=%28p-2w%29%2F2\"
\n" ); document.write( "\"L=%28202-2%2A44%29%2F2=%28101-44%29=57\" OR \"L=44\"\r
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\n" ); document.write( "\n" ); document.write( "Dimensions, however you want to assign them, or 44 and 57.
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