document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=949083>Question 949083</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the ages of a father and son is 46 years. In 2 years, four times the sun's age will equal the fathers age. What are their present ages? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579353 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579353\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F=father's age; S=son's age<BR>\n" );
document.write( "F+S=46 years<BR>\n" );
document.write( "F=46 years-S<BR>\n" );
document.write( "F+2=4(S+2) Substitute for F<BR>\n" );
document.write( "(46 years-S)+2=4S+8 Add S to each side<BR>\n" );
document.write( "48 years=5S+8 Subtract 8 from each side.<BR>\n" );
document.write( "40 years=5S Divide each side by 5.<BR>\n" );
document.write( "8 years=S ANSWER 1: The son is 8 years old.<BR>\n" );
document.write( "F=46 years-S=46 years-8 years=38 years  ANSWER 2: Father is 38 years old.<BR>\n" );
document.write( "CHECK: <BR>\n" );
document.write( "F+2=4(S+2)<BR>\n" );
document.write( "38 years + 2 years=4(8 years+2 years)<BR>\n" );
document.write( "40 years=4(10 years)<BR>\n" );
document.write( "40 years=40 years<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );