document.write( "Question 948989: How many real number solutions are there to the equation 0=-3x^2+x-4? \n" ); document.write( "

Algebra.Com's Answer #579291 by MathLover1(20849) $\"\"$ $\"About$

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\n" ); document.write( " $\"0=-3x%5E2%2Bx-4\"$ ....use discriminant to determine what kind of solutions you have in this case\r
\n" ); document.write( "\n" ); document.write( "Evaluate $\"b%5E2-4ac\"$
\n" ); document.write( " If the value is $\"b%5E2-4ac%3E0\"$ there are $\"two\"$ $\"+real\"$ unequal roots
\n" ); document.write( "If the value is $\"b%5E2-4ac=0\"$ there is $\"one\"$ real root, or $\"two\"$ equal $\"+real\"$ roots
\n" ); document.write( "If the value is $\"b%5E2-4ac%3C0\"$ there are two unequal $\"complex\"$ roots\r
\n" ); document.write( "\n" ); document.write( "In this case you get $\"b%5E2-4ac=1%5E2-4%2A%28-3%29%2A%28-4%29=1-4%2A12=1-48=-47\"$ \r
\n" ); document.write( "\n" ); document.write( "so, $\"-47%3C0\"$ and you have two unequal $\"complex\"$ roots\r
\n" ); document.write( "\n" ); document.write( "answer to the question how many $\"real\"$ number solutions are there is $\"zero\"$ or $\"none\"$ \n" ); document.write( "

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