document.write( "Question 948834: A broker sells a combined total of 40 shares of 2 different stocks.
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document.write( "The first stock sold for $12.25 per share , and the second stock sold for $15.75 per share. If the total sale was $539 how many shares of each stock were sold? \n" );
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Algebra.Com's Answer #579274 by macston(5194)![]() ![]() You can put this solution on YOUR website! X=shares of $12.25 stock; Y=shares of $15.75 stock \n" ); document.write( "X+Y=40 Solve for X \n" ); document.write( "X=40-Y \n" ); document.write( "$12.25(X)+$15.75(Y)=$539 Substitute for X \n" ); document.write( "$12.25(40-Y)+$15.75(Y)=$539 \n" ); document.write( "$490-$12.25Y+$15.75Y=$539 Subtract $490 from each side. \n" ); document.write( "$3.50Y=$49 Divide each side by $3.50 \n" ); document.write( "Y=14 ANSWER 1: 14 shares of the $15.75 stock were sold. \n" ); document.write( "X=40-Y=40-14=26 ANSWER 2: 26 shares 0f $12.25 stock were sold. \n" ); document.write( "CHECK \n" ); document.write( "Total sale=$539 \n" ); document.write( "$12.25(X)+$15.75(Y)=$539 \n" ); document.write( "$12.25(26)+$15.75(14)=$539 \n" ); document.write( "$318.50+$220.50=$539 \n" ); document.write( "$539=$539 \n" ); document.write( " |