document.write( "Question 948836: Ian and Lindsey are riding bikes in the same direction. Ian is traveling at an average speed of 12 miles per hour and passes a sign at 3:30 pm. Lindsey who is traveling at an average speed of 16 miles per hour, passes the same sign at 3:40 pm. At what time will Lindsey catch up with Ian? \n" ); document.write( "
Algebra.Com's Answer #579273 by ankor@dixie-net.com(22740)\"\" \"About 
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Ian and Lindsey are riding bikes in the same direction.
\n" ); document.write( " Ian is traveling at an average speed of 12 miles per hour and passes a sign at 3:30 pm.
\n" ); document.write( " Lindsey who is traveling at an average speed of 16 miles per hour, passes the same sign at 3:40 pm.
\n" ); document.write( " At what time will Lindsey catch up with Ian?
\n" ); document.write( ":
\n" ); document.write( "From the information given we know that at 3:30 Lindsey is 10 minutes behind Ian
\n" ); document.write( "find the distance Lindsey travels in 10 min
\n" ); document.write( "\"10%2F60\"*(16) = \"8%2F3\" mi Lindsey is behind Ian at 3:30
\n" ); document.write( ":
\n" ); document.write( "Let t = time required by L to catch I (in hrs)
\n" ); document.write( "then
\n" ); document.write( "16t = dist traveled by L
\n" ); document.write( "12t = dist traveled by I
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation,
\n" ); document.write( " L has to travel 8/3 of a mile more that Ian in the same time,
\n" ); document.write( "16t = 12t + \"8%2F3\"
\n" ); document.write( "16t - 12t = \"8%2F3\"
\n" ); document.write( "4t = \"8%2F3\"
\n" ); document.write( "t = \"8%2F3\"*\"1%2F4\"
\n" ); document.write( "t = \"8%2F12\" hr; which is \"8%2F12\"*60 = 40 min
\n" ); document.write( ":
\n" ); document.write( "3:30 + :40 = 4:10 L catches I
\n" ); document.write( "
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