document.write( "Question 948836: Ian and Lindsey are riding bikes in the same direction. Ian is traveling at an average speed of 12 miles per hour and passes a sign at 3:30 pm. Lindsey who is traveling at an average speed of 16 miles per hour, passes the same sign at 3:40 pm. At what time will Lindsey catch up with Ian? \n" ); document.write( "
Algebra.Com's Answer #579273 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Ian and Lindsey are riding bikes in the same direction. \n" ); document.write( " Ian is traveling at an average speed of 12 miles per hour and passes a sign at 3:30 pm. \n" ); document.write( " Lindsey who is traveling at an average speed of 16 miles per hour, passes the same sign at 3:40 pm. \n" ); document.write( " At what time will Lindsey catch up with Ian? \n" ); document.write( ": \n" ); document.write( "From the information given we know that at 3:30 Lindsey is 10 minutes behind Ian \n" ); document.write( "find the distance Lindsey travels in 10 min \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Let t = time required by L to catch I (in hrs) \n" ); document.write( "then \n" ); document.write( "16t = dist traveled by L \n" ); document.write( "12t = dist traveled by I \n" ); document.write( ": \n" ); document.write( "Write a distance equation, \n" ); document.write( " L has to travel 8/3 of a mile more that Ian in the same time, \n" ); document.write( "16t = 12t + \n" ); document.write( "16t - 12t = \n" ); document.write( "4t = \n" ); document.write( "t = \n" ); document.write( "t = \n" ); document.write( ": \n" ); document.write( "3:30 + :40 = 4:10 L catches I \n" ); document.write( " |