document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=948940>Question 948940</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a certain culture the rate of growth of bacteria is proportional to the amount present. Initially, 1000 bacteria are present and the amount doubles in 12 minutes. Determine the time it takes for the bacteria to multiply to 10,000. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579238 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579238\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In a certain culture the rate of growth of bacteria is proportional to the amount present. Initially, 1000 bacteria are present and the amount doubles in 12 minutes. Determine the time it takes for the bacteria to multiply to 10,000.<BR>\n" );
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document.write( "y = ab^x<BR>\n" );
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document.write( "y = 1000*2^(x/12)<BR>\n" );
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document.write( "Solve::<BR>\n" );
document.write( "10,000 = 1000*2^(x/12)<BR>\n" );
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document.write( "2^(x/12) = 10<BR>\n" );
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document.write( "(x/12) = log(10)/log(2)<BR>\n" );
document.write( "x = 12[1/0.3010]<BR>\n" );
document.write( "x = 39.86 minutes<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "--------------\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );