document.write( "Question 948907: The population of New Haven was 148,220 in 2005. Since then the population has been decreasing at an annual rate of 2.9%. If this rate of decline continues, what will the population be in the year 2015?\r
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document.write( "Y = a*bx where a is the starting amount; b is the decay rate (decreasing subtract from 1) ; x is time
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Algebra.Com's Answer #579187 by macston(5194)![]() ![]() You can put this solution on YOUR website! a=starting amount; b=decay rate (decreasing subtract from 1)(1-r) ; x is time; \n" ); document.write( "r=rate=2.9%=0.029 \n" ); document.write( "x=2015-2005=10 years \n" ); document.write( "This equation should be written: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Y=148220(.745)=110433 ANSWER: The population at this rate of decline will be 110,433 in 2015. \n" ); document.write( " |