document.write( "Question 948907: The population of New Haven was 148,220 in 2005. Since then the population has been decreasing at an annual rate of 2.9%. If this rate of decline continues, what will the population be in the year 2015?\r
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\n" ); document.write( "\n" ); document.write( "Y = a*bx where a is the starting amount; b is the decay rate (decreasing subtract from 1) ; x is time
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Algebra.Com's Answer #579187 by macston(5194)\"\" \"About 
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a=starting amount; b=decay rate (decreasing subtract from 1)(1-r) ; x is time;
\n" ); document.write( "r=rate=2.9%=0.029
\n" ); document.write( "x=2015-2005=10 years
\n" ); document.write( "This equation should be written:
\n" ); document.write( "\"Y+=+a%2Ab%5Ex\"
\n" ); document.write( "\"Y=a%281-r%29%5Ex\"
\n" ); document.write( "\"Y=148220%281-0.029%29%5E10\"
\n" ); document.write( "\"Y=148220%28.971%29%5E10\"
\n" ); document.write( "Y=148220(.745)=110433 ANSWER: The population at this rate of decline will be 110,433 in 2015.
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