document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=943116>Question 943116</A>: <I><SPAN STYLE=\"word-break: break-all;\"> difference of two numbers is 62,  the sum of twice the larer and three times the smaller is 304.   find the two numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579159 by </B><A HREF=/tutors/aboutme.mpl?userid=booklover15><B>booklover15(10)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=booklover15><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579159\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The bigger/larger number = b<BR>\n" );
document.write( "The smaller number = s<BR>\n" );
document.write( "b-s = 62 => b = 62 + s<BR>\n" );
document.write( "2b + 3s = 304<BR>\n" );
document.write( "And then we substitute the b<BR>\n" );
document.write( "2(62+s) + 3s = 304<BR>\n" );
document.write( "124 + 2s + 3s = 304<BR>\n" );
document.write( "5s = 304 - 124<BR>\n" );
document.write( "5s = 180<BR>\n" );
document.write( "s = 36<BR>\n" );
document.write( "Then we find the b<BR>\n" );
document.write( "b-s = 62<BR>\n" );
document.write( "b-36 = 62<BR>\n" );
document.write( "b = 62+36 = 98 </SPAN>\n" );
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