document.write( "Question 948849: amount being spent on personal phone calls followed a normal distribution with an average of $500/month and a standard eviation of $50/month. What is the probablity that a randomly selected month had a call expense between $375 and $590?\r
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\n" ); document.write( "\n" ); document.write( "I have come up with an answer of 0.9999 and 0.9579.
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Algebra.Com's Answer #579154 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
How do you have two answers?
\n" ); document.write( "You should only have 1.
\n" ); document.write( "Find the z score for both points.
\n" ); document.write( "\"z=%28x-mu%29%2Fsigma\"
\n" ); document.write( "\"z%5B1%5D=%28375-500%29%2F50=-2.5\"
\n" ); document.write( "\"z%5B2%5D=%28590-500%29%2F50=1.8\"
\n" ); document.write( "So then,
\n" ); document.write( "\"P=P%28z%5B2%5D%29-P%28z%5B1%5D%29\"
\n" ); document.write( "\"P=0.96407-0.00621\"
\n" ); document.write( "\"P=0.95786\"
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