document.write( "Question 948830: The measures of the angles in a triangle are in the extended ratio of 2:5:8. Find the measure of the three angles. \n" ); document.write( "
Algebra.Com's Answer #579124 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "Recall that the sum of the interior angles of any triangle is \"180\"°. \r
\n" ); document.write( "\n" ); document.write( " let \"+k\"be an arbitrary constant of proportionality \r
\n" ); document.write( "\n" ); document.write( "you are given: given that the ratio of the angles is given as \"2%3A5%3A8\", we can say:\r
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\n" ); document.write( "\n" ); document.write( "\"2k+%2B5k+%2B8k+=+180\"\r
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\n" ); document.write( "\n" ); document.write( "Solve for \"+k\" and then calculate \"+5k\" and \"+8k\" to get the measure of the three angles. \r
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\n" ); document.write( "\n" ); document.write( "\"15k+=+180\"\r
\n" ); document.write( "\n" ); document.write( "\"k+=+180%2F15\"\r
\n" ); document.write( "\n" ); document.write( "\"k+=+12\"\r
\n" ); document.write( "\n" ); document.write( "your angles:\r
\n" ); document.write( "\n" ); document.write( "\"2k=2%2A12=24\"\r
\n" ); document.write( "\n" ); document.write( "\"+5k=5%2A12=60\" \r
\n" ); document.write( "\n" ); document.write( "and \"+8k=8%2A12=96\"\r
\n" ); document.write( "\n" ); document.write( "so, your angles are: \"24\",\"60\",and \"96\"\r
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