document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=948819>Question 948819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A wire that is 76 inches lonh is bent to form a rectangle. If the length of this rectangle is 7 inches less than twice its width, then what is the area of the rectangle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579118 by </B><A HREF=/tutors/aboutme.mpl?userid=booklover15><B>booklover15(10)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=booklover15><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579118\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Length = Width - 7<BR>\n" );
document.write( "L = W-7\r<BR>\n" );
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document.write( "76 = 2 ( L+W)<BR>\n" );
document.write( "76/2 = L + W<BR>\n" );
document.write( "38 = L + W<BR>\n" );
document.write( "38 = W - 7 + W<BR>\n" );
document.write( "38 + 7 = 2W<BR>\n" );
document.write( "45 = 2W<BR>\n" );
document.write( "W = 45/2 <BR>\n" );
document.write( "W = 22.5\r<BR>\n" );
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document.write( "L = W -7<BR>\n" );
document.write( "L = 22.5 - 7 = 15.5 \r<BR>\n" );
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document.write( "A = 15.5 x 22.5 = 348. 75 </SPAN>\n" );
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