document.write( "Question 948728: How do you solve 3/4x=60 \n" ); document.write( "
Algebra.Com's Answer #579097 by jim_thompson5910(35256)\"\" \"About 
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If the equation is \"expr%283%2F4%29x=60\", then...\r
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\n" ); document.write( "\n" ); document.write( "\"expr%283%2F4%29x=60\"\r
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\n" ); document.write( "\n" ); document.write( "\"4%2Aexpr%283%2F4%29x=4%2A60\" Multiply both sides by 4\r
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\n" ); document.write( "\n" ); document.write( "\"3x=240\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2F3=240%2F3\" Divide both sides by 3.\r
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\n" ); document.write( "\n" ); document.write( "\"x=80\"\r
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\n" ); document.write( "\n" ); document.write( "OR if the equation is \"3%2F%284x%29=60\", then...\r
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\n" ); document.write( "\n" ); document.write( "\"3%2F%284x%29=60\"\r
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\n" ); document.write( "\n" ); document.write( "\"%283%2F%284x%29%29%2A4x=60%2A4x\" Multiply both sides by 4x.\r
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\n" ); document.write( "\n" ); document.write( "\"3=240x\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%2F240=240x%2F240\" Divide both sides by 240.\r
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\n" ); document.write( "\n" ); document.write( "\"3%2F240+=+x\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F80+=+x\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+1%2F80\"
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