document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=948697>Question 948697</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive integers such that three times the sum of the first and the last is 552. Help would be appreciated, been trying to solve it for about a day. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #579074 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=579074\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First integer=X; Last integer=X+2<BR>\n" );
document.write( "3(X+(X+2))=552 Divide each side by 3<BR>\n" );
document.write( "2X+2=184 Subtract 2 from each side<BR>\n" );
document.write( "2X=182 Divide each side by 2<BR>\n" );
document.write( "X=91 ANSWER 1: The first integer is 91.<BR>\n" );
document.write( "X+2=91+2=93 ANSWER 2: The last integer is 93<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "Three times the sum is 552<BR>\n" );
document.write( "552=3(91+93)<BR>\n" );
document.write( "552=3(184)<BR>\n" );
document.write( "552=552<BR>\n" );
document.write( "The middle integer is X+1=92, not needed in this problem. </SPAN>\n" );
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