document.write( "Question 948631: The perimeter of a rectangle is 160 meters. If the length is 20 meters less than three times the width, find the dimensions of the rectangle.\r
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document.write( " What is the length?\r
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document.write( "What is the width? \n" );
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Algebra.Com's Answer #579037 by macston(5194)![]() ![]() You can put this solution on YOUR website! W=width; L=length=3W-20; Perimeter=2(L+W) \n" ); document.write( "160 meters=2(L+W) Substitute for L \n" ); document.write( "160 meters=2((3W-20)+W) Divide each side by 2. \n" ); document.write( "80 meters=4W-20 Add 20 to each side. \n" ); document.write( "100 meters=4W Divide each side by 4 \n" ); document.write( "25 meters=W ANSWER 1: The width is 25 meters. \n" ); document.write( "L=3W-20=3(25)-20=75-20=55 meters ANSWER 2: The length is 55 meters \n" ); document.write( "CHECK \n" ); document.write( "P=2(L+W) \n" ); document.write( "160 meters=2(55 meters + 25 Meters) \n" ); document.write( "160 meters=2(80 meters) \n" ); document.write( "160 meters=160 meters\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |