document.write( "Question 948575: Please help me answer this: show that m(x^2-x)+1-m=x^2 has real roots for all real values of m. (P.S. Do forgive me for all the inconvenience.) \n" ); document.write( "
Algebra.Com's Answer #579002 by josgarithmetic(39626)\"\" \"About 
You can put this solution on YOUR website!
\"m%28x%5E2-x%29%2B1-m=x%5E2\"
\n" ); document.write( "Quadratic equation with \"unknown\" x, and constant m.
\n" ); document.write( "Real roots? Discriminant must be non-negative.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"mx%5E2-mx%2B1-m-x%5E2=0\"
\n" ); document.write( "\"mx%5E2-x%5E2-mx%2B1-m=0\"
\n" ); document.write( "\"%28m-1%29x%5E2-mx%2B%281-m%29=0\", the given equation now in general form.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Inequality for the discriminant needed:
\n" ); document.write( "\"highlight_green%28m%5E2-4%28m-1%29%281-m%29%3E=0%29\", left member is the discriminant.
\n" ); document.write( "\"m%5E2-4%28m-1%29%28-1%29%28m-1%29%3E=0\"
\n" ); document.write( "\"m%5E2%2B4%28m-1%29%5E2%3E=0\"
\n" ); document.write( "\"m%5E2%2B4%28m%5E2-2m%2B1%29%3E=0\"
\n" ); document.write( "\"m%5E2%2B4m%5E2-8m%2B4%3E=0\"
\n" ); document.write( "\"highlight_green%285m%5E2-8m%2B4%3E=0%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The truth of this m inequality depends on no real roots for m, meaning the discriminant of just the m inequality must be NEGATIVE.
\n" ); document.write( "If \"%28-8%29%5E2-4%2A5%284%29%3C0\", then the m quadratic inequality has no real roots.
\n" ); document.write( "\"64-20%2A4%3C0\"
\n" ); document.write( "\"64-80%3C0\"
\n" ); document.write( "\"highlight_green%28-16%3C0%29\"------TRUE.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "That truth means that the \"5m%5E2-8m%2B4%3E=0\" is satisfied; and that means that the original given equation will have real roots (for all m).
\n" ); document.write( "
\n" );