document.write( "Question 948509: Suppose 9 quarts of a solution that is 95% antifreeze is mixed with 7 quarts of a solution that is 55% antifreeze. \r
\n" ); document.write( "\n" ); document.write( "(a) How many quarts of antifreeze are in the resulting mixture?
\n" ); document.write( "Quarts ___________\r
\n" ); document.write( "\n" ); document.write( "(b) What percentage of the resulting mixture is antifreeze?
\n" ); document.write( "% ___________
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Algebra.Com's Answer #578968 by macston(5194)\"\" \"About 
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9 qts of 95% antifreeze =0.95(9 qts)=8.55 qts antifreeze
\n" ); document.write( "7 qts of 55% antifreeze =0.55(7 qts)=3.85 qts antifreeze
\n" ); document.write( "The mixture contains 8.55 qts+3.85 qts=12.4 qts antifreeze
\n" ); document.write( "ANSWER 1: The resulting mix contains 12.4 qts antifreeze.
\n" ); document.write( "There are a total of 9 qts+7 qts=16 qts
\n" ); document.write( "(12.4 qts/16 qts)(100%)=77.5%
\n" ); document.write( "ANSWER 2: The resulting mix is 77.5% antifreeze.
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