document.write( "Question 948473: A car travels along a straight road at a speed of 5 km/h (kilometres
\n" ); document.write( "per hour). Another car starts at the same time from the same point
\n" ); document.write( "and travels along a perpendicular direction with speed 12 km/h.
\n" ); document.write( "When will the two cars be at a distance 65 km apart?
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Algebra.Com's Answer #578967 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A car travels along a straight road at a speed of 5 km/h (kilometres
\n" ); document.write( "per hour).
\n" ); document.write( "Another car starts at the same time from the same point
\n" ); document.write( "and travels along a perpendicular direction with speed 12 km/h.
\n" ); document.write( "When will the two cars be at a distance 65 km apart?
\n" ); document.write( ":
\n" ); document.write( "let t = time in hrs when they will be 65 km apart
\n" ); document.write( "then
\n" ); document.write( "5t = distance traveled by the first car (dist = speed * time)
\n" ); document.write( "and
\n" ); document.write( "12t = distance traveled by the 2nd car
\n" ); document.write( ":
\n" ); document.write( "This is a pythag problem, a^2 + b^2 = c^2, where:
\n" ); document.write( "a = 5t
\n" ); document.write( "b = 12t
\n" ); document.write( "c = 65
\n" ); document.write( ":
\n" ); document.write( "(5t)^2 + (12t)^2 = 65^2
\n" ); document.write( "25t^2 + 144t^2 = 4225
\n" ); document.write( "169t^2 = 4225
\n" ); document.write( "t^2 = 4225/169
\n" ); document.write( "t^2 = 25
\n" ); document.write( "t = \"sqrt%2825%29\"
\n" ); document.write( "t = 5 hrs for them to be 65 mi apart
\n" ); document.write( ":
\n" ); document.write( ";
\n" ); document.write( "Check this on your calc: enter \"sqrt%2825%5E2+%2B+60%5E2%29%29\"
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