document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=948501>Question 948501</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Doug will make two $8000 investments. If one account yields 11%, what should the interest rate be on the other account to make a yearly total of $1720 in interest? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #578960 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=578960\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I=Interest on second account<BR>\n" );
document.write( "Subtract interest paid at 11% from total interest to get interest on second account only.  Divide this by second account amount and multiply by 100% to get percent interest.<BR>\n" );
document.write( "(($1720-($8000*.11))/$8000)(100%)=I <BR>\n" );
document.write( "(($1720-$880)/$8000)(100%)=I<BR>\n" );
document.write( "($840/$8000)(100%)=I<BR>\n" );
document.write( "(0.105)(100%)=I<BR>\n" );
document.write( "10.5%=I <BR>\n" );
document.write( "ANSWER: The interest rate on the second account should be 10.5% to achieve a total return of $1720 on the investments.  <BR>\n" );
document.write( " </SPAN>\n" );
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