document.write( "Question 948385: Two cars left the intersection @ the same time. One traveled west and the other traveled 14 miles less but south. How far apart were they @ the time if the distance between them was 16 miles more than the distance traveled south? \n" ); document.write( "
Algebra.Com's Answer #578958 by ankor@dixie-net.com(22740)    You can put this solution on YOUR website! Two cars left the intersection @ the same time. \n" ); document.write( " One traveled west and the other traveled 14 miles less but south. \n" ); document.write( " How far apart were they @ the time if the distance between them was 16 miles more than the distance traveled south? \n" ); document.write( ": \n" ); document.write( "let a = distance traveled by the south bound car \n" ); document.write( "then \n" ); document.write( "(a+14) = distance traveled by the west bound \n" ); document.write( "and \n" ); document.write( "(a+16) = distance between them at a certain time \n" ); document.write( ": \n" ); document.write( "This is a pythag problem a^2 + b^2 = c^2, where \n" ); document.write( "a = a \n" ); document.write( "b = (a+14) \n" ); document.write( "c = (a+16) \n" ); document.write( ": \n" ); document.write( "a^2 + (a+14)^2 = (a+16)^2 \n" ); document.write( "FOIL \n" ); document.write( "a^2 + a^2 + 28a + 196 = a^2 + 32a + 256 \n" ); document.write( "Collect like terms on the left \n" ); document.write( "a^2 + a^2 - a^2 + 28a - 32a + 196 - 256 = 0 \n" ); document.write( "do the math \n" ); document.write( "a^2 - 4a - 60 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(a- - 10)(a + 6) = 0 \n" ); document.write( "the positive solution is all we want here \n" ); document.write( "a = 10 \n" ); document.write( "therefore the distance between them \n" ); document.write( "10 + 16 = 26 miles \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "Check this on your calc, enter  |