document.write( "Question 948395: The nickels and dimes fell on the floor. There were 12 more nickels than dimes, and the total value of the coins was $5.10. How many nickels and how manh dimes were on the floor? \n" ); document.write( "
Algebra.Com's Answer #578923 by macston(5194)\"\" \"About 
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D=Dimes; N=Nickels
\n" ); document.write( "N=D+12
\n" ); document.write( "$0.05N+$0.10D=$5.10 Substitute for N
\n" ); document.write( "$0.05(D+12)+$0.10D=$5.10
\n" ); document.write( "$0.05D+$0.60+$0.10D=$5.10 Subtract $0.60 from each side.
\n" ); document.write( "$0.15D=$4.50 Divide each side by $0.15
\n" ); document.write( "D=30 ANSWER 1: There were 30 dimes.
\n" ); document.write( "N=D+12=30+12=42 ANSWER 2: There were 42 nickels.
\n" ); document.write( "CHECK:
\n" ); document.write( "$0.05(N)+$0.10(D)=$5.10
\n" ); document.write( "$0.05(42)+$0.10(30)=$5.10
\n" ); document.write( "$2.10+$3.00=$5.10
\n" ); document.write( "$5.10=$5.10\r
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