document.write( "Question 948439: A vineyard’s grapes can be harvested by 10 workers in 5 hours. If one worker starts the
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document.write( "harvest at noon, and another worker joins the harvest each hour on the hour, at what time
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document.write( "will the harvest be completed? \n" );
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Algebra.Com's Answer #578913 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! r, rate for one worker. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First hour, \n" ); document.write( "\n" ); document.write( "Hour Number Two, two workers, when completed time: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hour Number Three, three workers, when completed time: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "UNKNOWN number of hours completed, for finishing harvesting the vineyard's grapes: \n" ); document.write( "(1/50)(1+2+3+...n)=1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1+2+3+...n=50\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "OR in renderable notational form \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n=10.69, more than ten hours but less than eleven hours. \n" ); document.write( "The actual time from start to finish would be 10 hours 41 minutes. \n" ); document.write( " |