document.write( "Question 948439: A vineyard’s grapes can be harvested by 10 workers in 5 hours. If one worker starts the
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Algebra.Com's Answer #578913 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
r, rate for one worker.
\n" ); document.write( "\"10r%2A5=1\", the one job of THE VINEYARDS GRAPES.
\n" ); document.write( "\"r=1%2F50\".\r
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\n" ); document.write( "\n" ); document.write( "First hour, \"1%2Ar%2A1=%281%2F50%29\", a small amount of the job done.\r
\n" ); document.write( "\n" ); document.write( "Hour Number Two, two workers, when completed time:
\n" ); document.write( "\"%281%2F50%29%2A1%2B%282%2F50%29%2A1\"\r
\n" ); document.write( "\n" ); document.write( "Hour Number Three, three workers, when completed time:
\n" ); document.write( "\"1%2F50%2B2%2F50%2B%283%2F50%29%2A1\"\r
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\n" ); document.write( "\n" ); document.write( "UNKNOWN number of hours completed, for finishing harvesting the vineyard's grapes:
\n" ); document.write( "(1/50)(1+2+3+...n)=1\r
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\n" ); document.write( "\n" ); document.write( "1+2+3+...n=50\r
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\n" ); document.write( "\n" ); document.write( "OR in renderable notational form
\n" ); document.write( "\"sum%28x%2Ci=1%2Cn%29=50\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28n%2F2%29%281%2Bn%29=50\"\r
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\n" ); document.write( "\n" ); document.write( "\"n%281%2Bn%29=100\"\r
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\n" ); document.write( "\n" ); document.write( "\"n%5E2%2Bn=100\"\r
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\n" ); document.write( "\n" ); document.write( "\"n%5E2%2Bn-100=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"n=%28-1%2B-+sqrt%281%2B4%2A100%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"n=%28-1%2Bsqrt%28501%29%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "n=10.69, more than ten hours but less than eleven hours.
\n" ); document.write( "The actual time from start to finish would be 10 hours 41 minutes.
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