document.write( "Question 948428: A person drove 24 mph on a trip. If he had driven 36 mph he would have arrived 2 hours earlier. What was the distance traveled? \n" ); document.write( "
Algebra.Com's Answer #578911 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "A person drove 24 mph on a trip. If he had driven 36 mph he would have arrived 2 hours earlier. What was the distance traveled?
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\n" ); document.write( "Let distance driven, be D
\n" ); document.write( "Then time taken = \"D%2F24\"
\n" ); document.write( "Time he/she would’ve taken had he/she driven 36 mph: \"D%2F36\"
\n" ); document.write( "With difference in time being 2 hours, we get:
\n" ); document.write( "\"D%2F24+=+D%2F36+%2B+2\"
\n" ); document.write( "3D = 2D + 144 ------- Multiplying by LCD, 72
\n" ); document.write( "3D – 2D = 144
\n" ); document.write( "D, or distance traveled = \"highlight_green%28144%29\" miles \n" ); document.write( "
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