document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=948427>Question 948427</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a man is 3 times as old as his son. In 12 years time he will be twice as old as his son. How old is both of them? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #578902 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=578902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F=Father's age=3S; S=Son's age<BR>\n" );
document.write( "F=3S<BR>\n" );
document.write( "F+12=2(S+12) Substitute for F<BR>\n" );
document.write( "3S+12=2(S+12)<BR>\n" );
document.write( "3S+12=2S+24 Subtract 2S from each side.<BR>\n" );
document.write( "S+12=24 Subtract 12 from each side.<BR>\n" );
document.write( "S=12 ANSWER 1:The son is 12 years old.<BR>\n" );
document.write( "F=3S=3(12)=36 years old ANSWER 2: The father is 36 years old.<BR>\n" );
document.write( "CHECK: <BR>\n" );
document.write( "In 12 years:<BR>\n" );
document.write( "F+12 years=2(S+12 years)<BR>\n" );
document.write( "36+12=2(12+12)<BR>\n" );
document.write( "48 years =48 years </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );