document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=948429>Question 948429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle is 6 feet long and has a perimeter of 20 1/3 feet what is the width  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #578900 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=578900\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=length; W=width;P=perimeter=2(L+W)<BR>\n" );
document.write( "20 1/3 ft=2(6 ft+W) <BR>\n" );
document.write( "20 1/3 ft=12 ft +2W Subtract 12 from each side.<BR>\n" );
document.write( "8 1/3 feet=2W Divide each side by 2<BR>\n" );
document.write( "4 1/6 feet=W ANSWER: The width of the rectangle is 4 feet 2 inches.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "20 1/3 ft=2(6 ft+4 1/6 ft)<BR>\n" );
document.write( "20 1/3 ft=2(10 1/6 ft)<BR>\n" );
document.write( "20 1/3 ft=20 1/3 ft<BR>\n" );
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