document.write( "Question 948400: How would I find the x and y-intercept and vertex of: H(x)=3x-1/2x^2\r
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Algebra.Com's Answer #578886 by macston(5194)![]() ![]() You can put this solution on YOUR website! H(x)=3x-1/2x^2 Write the equation in the form: \n" ); document.write( " \n" ); document.write( "In this case: \n" ); document.write( " \n" ); document.write( " The x-intercept is where y=0 so \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The answers are 0 and 6, so the x-intercepts are (0,0) and (6,0) \n" ); document.write( "And the y-intercept(s) is where x=0, so: \n" ); document.write( " \n" ); document.write( "y=0 So the y-intercept is at the origin (0,0) \n" ); document.write( "The axis of symmetry is given by: (This is the x value of the vertex) \n" ); document.write( " \n" ); document.write( "In this case: \n" ); document.write( " \n" ); document.write( "x=3 Substitute this in the original equation to get the y value of the vertex. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "y=4.5 So the vertex is (3,4.5)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |