document.write( "Question 948369: state the intervals where the function is increasing, decreasing, or constant.\r
\n" ); document.write( "\n" ); document.write( "The function is: f(x)=-1|x-2|+2
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Algebra.Com's Answer #578880 by josgarithmetic(39621)\"\" \"About 
You can put this solution on YOUR website!
The critical value is at x=2. The function is split to two branches around x=2.\r
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\n" ); document.write( "\n" ); document.write( "CASE \"x%3C2\":
\n" ); document.write( "\"-1%28abs%28x-2%29%29%2B2\"
\n" ); document.write( "\"-1%2A%28-1%29%28x-2%29%2B2\" because \"x-2%3C0\";
\n" ); document.write( "\"%28x-2%29%2B2\"
\n" ); document.write( "\"x\"\r
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\n" ); document.write( "\n" ); document.write( "CASE \"x%3E=2\":
\n" ); document.write( "\"f%28x%29=-1%28x-2%29%2B2\"
\n" ); document.write( "\"-x%2B2%2B2\"
\n" ); document.write( "\"-x%2B4\"\r
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\n" ); document.write( "\n" ); document.write( "Definition for f:
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\n" ); document.write( "\"f%28x%29=x\" if \"x%3C2\" and f is increasing.
\n" ); document.write( "\"f%28x%29=-x%2B4\" if \"x%3E=2\" and f is decreasing (see the negative slope).
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\n" ); document.write( "\n" ); document.write( "Sometimes my work appears to skip a step.
\n" ); document.write( "Be aware of this idea: \"a-b\" is an expression;
\n" ); document.write( "\"-%28a-b%29=-1%2A%28a-b%29\"
\n" ); document.write( "\"-1%2Aa-%28-1%29b\"
\n" ); document.write( "\"-a%2Bb\"
\n" ); document.write( "\"b-a\"
\n" ); document.write( "-
\n" ); document.write( "Shorter, \"-%28a-b%29=b-a\"
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