document.write( "Question 948381: Company A Spent a total of $11 million on advertising in fiscal year 2010, 2011, and 2012. The amount spent in 2012 was three times the amount spent in 2010. The amount spent in 2011 was $3 million less than the amount spent in 2012. How much was spent on advertising each year.\r
\n" ); document.write( "\n" ); document.write( "My attempt to set-up the system:\r
\n" ); document.write( "\n" ); document.write( "x + y + z = 11
\n" ); document.write( " y - z = 3
\n" ); document.write( " z = 3x \n" ); document.write( "

Algebra.Com's Answer #578877 by MathLover1(20850) $\"\"$ $\"About$

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Company A Spent a total of $ $\"11\"$ million on advertising in fiscal year $\"2010\"$ , $\"+2011\"$ , and $\"2012\"$ . \r
\n" ); document.write( "\n" ); document.write( "your attempt to set-up the system was perfect, system just need to be solved\r
\n" ); document.write( "\n" ); document.write( "so,
\n" ); document.write( "in year $\"2010\"$ company spent $\"x\"$ million,
\n" ); document.write( "in year $\"2011\"$ company spent $\"y\"$ million,
\n" ); document.write( "in year $\"2012\"$ company spent $\"z\"$ million, \r
\n" ); document.write( "\n" ); document.write( "total: $\"x%2By%2Bz=11\"$ ........eq.1\r
\n" ); document.write( "\n" ); document.write( "The amount $\"z\"$ spent in $\"2012\"$ was three times the amount $\"x\"$ spent in $\"2010\"$ .
\n" ); document.write( " $\"z=3x\"$ ........eq.2\r
\n" ); document.write( "\n" ); document.write( "The amount $\"y\"$ spent in $\"2011\"$ was $ $\"3\"$ million less than the amount $\"z\"$ spent in $\"2012\"$ .
\n" ); document.write( " $\"y=z-3\"$ ........eq.3\r
\n" ); document.write( "\n" ); document.write( "solve the system:
\n" ); document.write( " $\"x%2By%2Bz=11\"$ ........eq.1
\n" ); document.write( " $\"z=3x\"$ ........eq.2
\n" ); document.write( " $\"y=z-3\"$ ........eq.3
\n" ); document.write( "-----------------------------------------
\n" ); document.write( "start with $\"y=z-3\"$ ........eq.3 substitute $\"z%7D%7D+from+eq.2%0D%0A%7B%7B%7By=3x-3\"$ .......3a\r
\n" ); document.write( "\n" ); document.write( "go to
\n" ); document.write( " $\"x%2By%2Bz=11\"$ ........eq.1 substitute $\"z%7D%7D+from+eq.2+and+%7B%7B%7By\"$ from eq.3a
\n" ); document.write( " $\"x%2B3x-3%2B3x=11\"$ ...... solve for $\"x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"7x=11%2B3\"$
\n" ); document.write( " $\"7x=14\"$
\n" ); document.write( " $\"x=14%2F7\"$
\n" ); document.write( " $\"highlight%28x=2%29\"$ \r
\n" ); document.write( "\n" ); document.write( "go to $\"y=3x-3\"$ .......3a substitute $\"2%7D%7D+for++%7B%7B%7Bx%7D%7D%0D%0A%0D%0A%7B%7B%7By=3%2A2-3\"$
\n" ); document.write( " $\"y=6-3\"$
\n" ); document.write( " $\"highlight%28y=3%29\"$ \r
\n" ); document.write( "\n" ); document.write( "go to $\"z=3x\"$ ........eq.2 substitute $\"2%7D%7D+for++%7B%7B%7Bx%7D%7D%0D%0A%0D%0A%7B%7B%7Bz=3%2A2\"$
\n" ); document.write( " $\"highlight%28z=6%29\"$ \r
\n" ); document.write( "\n" ); document.write( "so, each year on advertising was spent: \r
\n" ); document.write( "\n" ); document.write( "in year $\"2010\"$ company spent $\"2\"$ million,
\n" ); document.write( "in year $\"2011\"$ company spent $\"3\"$ million,
\n" ); document.write( "in year $\"2012+\"$ company spent $\"6\"$ million,
\n" ); document.write( " \n" ); document.write( "

\n" );