document.write( "Question 948396: If P(A) = 0.5, P(AandB) = 0.3, and P(AorB) = 0.6, find P(B).
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document.write( "A an B are independent events. P(A) = 0.3, and P(A or B) = 0.8. Find P(B). The more I see, the more I get confused.
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document.write( "Thanks in advance. \n" );
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Algebra.Com's Answer #578873 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! If P(A) = 0.5, P(AandB) = 0.3, and P(AorB) = 0.6, find P(B).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(A or B) = P(A) + P(B) - P(A and B) \n" ); document.write( "0.6 = 0.5 + P(B) - 0.3 \n" ); document.write( "0.6 = 0.2 + P(B) \n" ); document.write( "0.6 - 0.2 = P(B) \n" ); document.write( "0.4 = P(B) \n" ); document.write( "P(B) = 0.4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A an B are independent events. P(A) = 0.3, and P(A or B) = 0.8. Find P(B). \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = P(B)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"A an B are independent events\" so P(A and B) = P(A)*P(B)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(A or B) = P(A) + P(B) - P(A and B) \n" ); document.write( "P(A or B) = P(A) + P(B) - P(A)*P(B) \n" ); document.write( "0.8 = 0.3 + x - 0.3*x \n" ); document.write( "0.8 = 0.3 + 0.7*x \n" ); document.write( "0.8 - 0.3 = 0.7*x \n" ); document.write( "0.5 = 0.7*x \n" ); document.write( "0.5/0.7 = x \n" ); document.write( "5/7 = x \n" ); document.write( "x = 5/7 \n" ); document.write( "x = 0.71429 (this is approximate)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(B) = 5/7 which is approximately 0.71429 \n" ); document.write( " |