document.write( "Question 948358: The perimeter of a rectangle is 260 m. If the length is 5 m less than twice the width, find the dimensions of the rectangle.
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document.write( "What is the length?
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document.write( "What is the width? \n" );
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Algebra.Com's Answer #578852 by macston(5194)![]() ![]() You can put this solution on YOUR website! W=width; L=length=2W-5; Perimeter=P=2(L+W)=260 m \n" ); document.write( "P=2(L+W) Substitute for L \n" ); document.write( "260 m=2((2W-5)+W) \n" ); document.write( "260 m=2(3w-5) Divide each side by 2 \n" ); document.write( "130 m=3W-5 Add 5 to each side \n" ); document.write( "135 m=3W Divide each side by 3 \n" ); document.write( "45 m=W ANSWER 1: Width is 45 meters. \n" ); document.write( "L=2W-5=2(45)-5=90-5=85 m ANSWER 2: Length is 85 meters \n" ); document.write( "CHECK: \n" ); document.write( "P=260 m=2(L+W)=2(85 m+45 m) \n" ); document.write( "260 m=2(130 m) \n" ); document.write( "260 m=260 m\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |