document.write( "Question 948358: The perimeter of a rectangle is 260 m. If the length is 5 m less than twice the width, find the dimensions of the rectangle.
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\n" ); document.write( "What is the width?
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Algebra.Com's Answer #578852 by macston(5194)\"\" \"About 
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W=width; L=length=2W-5; Perimeter=P=2(L+W)=260 m
\n" ); document.write( "P=2(L+W) Substitute for L
\n" ); document.write( "260 m=2((2W-5)+W)
\n" ); document.write( "260 m=2(3w-5) Divide each side by 2
\n" ); document.write( "130 m=3W-5 Add 5 to each side
\n" ); document.write( "135 m=3W Divide each side by 3
\n" ); document.write( "45 m=W ANSWER 1: Width is 45 meters.
\n" ); document.write( "L=2W-5=2(45)-5=90-5=85 m ANSWER 2: Length is 85 meters
\n" ); document.write( "CHECK:
\n" ); document.write( "P=260 m=2(L+W)=2(85 m+45 m)
\n" ); document.write( "260 m=2(130 m)
\n" ); document.write( "260 m=260 m\r
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